关于laravel 子查询 & join的使用
发布:smiling 来源: PHP粉丝网 添加日期:2022-01-06 10:35:30 浏览: 评论:0
今天小编就为大家分享一篇关于laravel 子查询 & join的使用,具有很好的参考价值,希望对大家有所帮助,一起跟随小编过来看看吧。
本项目中关联了2个数据库
- 'default' => env('DB_CONNECTION', 'mysql'), //默认使用mysql为连接库
- 'connections' => [
- 'mysql' => [
- 'driver' => 'mysql',
- 'host' => '192.168.0.xx',
- 'database' => 'database',
- 'username' => 'root',
- 'password' => '',
- 'charset' => 'utf8',
- 'collation' => 'utf8_unicode_ci',
- 'prefix' => 'tb_',
- 'strict' => false,
- ],
- 'mysql_snapshot' => [
- 'driver' => 'mysql',
- 'host' => env('DB_HOST_SNAPSHOT', '192.168.0.xx'),
- 'database' => env('DB_DATABASE_SNAPSHOT', 'snapshot'),
- 'username' => env('DB_USERNAME_SNAPSHOT', 'root'),
- 'password' => env('DB_PASSWORD_SNAPSHOT', ''),
- 'charset' => 'utf8',
- 'collation' => 'utf8_unicode_ci',
- 'prefix' => 'tb_',
- 'strict' => false,
- ],
- ],
在某个需求中,需要使用子查询获取snapshot快照表库的关联数据,从而实现以下sql逻辑。
- SELECT ... From
- (SELECT
- sum(game_count) AS sum_count,
- max(game_count) AS max_count,
- game_room_id,
- record_date
- FROM
- `tb_xx_snapshot`
- WHERE
- record_date BETWEEN '2017-05-17' AND '2017-05-23'
- AND
- type = '1'
- GROUP BY
- game_room_id) as main
- INNER JOIN `tb_xx_snapshot` AS `tb_gg` ON tb_gg.game_count = main.max_count and tb_gg.game_room_id = main.game_room_id
- where
- tb_gg.record_date BETWEEN '2017-05-17' AND '2017-05-23'
- AND
- tb_gg.type = '1'
- GROUP BY
- tb_gg.game_room_id;
其中子查询主要用到以下query builder语句
- $query = DB::table('xx_snapshot')->where('xx','yy')->groupBy('xx');
- $main = DB::connection('mysql_snapshot')
- ->table(DB::raw("({$query->toSql()}) as tb_main"))
- ->mergeBindings($query->getQuery()) // 绑定参数,否则sql语句会只有'?'
- ->get();
而join语句中可传入匿名函数重新构造,如再其中加多几个连接条件,或者查询条件
- $con = DB::table('xx_snapshot')
- ->join('xx_snapshot as gg', function ($query) {
- $query->on('gg.game_count', '=', 'xx_snapshot.max_count')
- ->on('gg.game_room_id', '=', 'xx_snapshot.game_room_id')
- ->where('gg.xx','123';
- })
实现上述需求完整代码如下:
- $subQuery= GameroomModel::select(DB::raw('sum(game_count) as sum_count,max(game_count) as max_count,record_date,game_room_id'))
- ->whereBetween('record_date',[$beginDay,$endDay])
- ->where('type','1')
- ->groupBy('game_room_id');
- $main = DB::connection('mysql_snapshot')
- ->table(DB::raw("({$subQuery->toSql()}) as tb_main"))
- ->mergeBindings($playerGame->getQuery())
- ->join('gameroom_snapshot as gg', function ($join) {
- $join->on('gg.game_count', '=', 'main.max_count')
- ->on('gg.game_room_id', '=', 'main.game_room_id');
- })
- - >select('main.max_count','main.sum_count','gg.record_date','main.game_room_id')
- ->whereBetween('gg.record_date',[$beginDay,$endDay])
- ->groupBy('main.game_room_id')
- ->get();
代码中子查询和外层都group by了一次,应该可以再优化一下.
Tags: laravel子查询 join
相关文章
- ·解决在laravel中leftjoin带条件查询没有返回右表为NULL的问题(2022-01-04)
- ·Laravel 连接(Join)示例(2022-01-06)
- ·laravel高级的Join语法详解以及使用Join多个条件(2022-01-06)
推荐文章
热门文章
最新评论文章
- 写给考虑创业的年轻程序员(10)
- PHP新手上路(一)(7)
- 惹恼程序员的十件事(5)
- PHP邮件发送例子,已测试成功(5)
- 致初学者:PHP比ASP优秀的七个理由(4)
- PHP会被淘汰吗?(4)
- PHP新手上路(四)(4)
- 如何去学习PHP?(2)
- 简单入门级php分页代码(2)
- php中邮箱email 电话等格式的验证(2)