mysql中查询今天,昨天,上个月sql语句
发布:smiling 来源: PHP粉丝网 添加日期:2014-10-04 15:51:23 浏览: 评论:0
本文章给各位同学介绍mysql中查询今天,昨天,上个月sql语句,有需要了解的朋友可参考.
今天 select * from 表名 where to_days(时间字段名) = to_days(now());
昨天Select * FROM 表名 Where TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1
7天Select * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)
近30天Select * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)
本月Select * FROM 表名 Where DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )
上一月Select * FROM 表名 Where PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1
#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查询上个月的数据:
- select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
- select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;
- select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
- select *
- from user
- where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
- select *
- from [ user ]
- where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
- and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
- select *
- from [ user ]
- where pudate between 上月最后一天
- and 下月第一天
- where date(regdate) = curdate();
- select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())
- SELECT date( c_instime ) ,curdate( )
- FROM `t_score` //phpfensi.com
- WHERE 1
- LIMIT 0 , 30
Tags: mysql查询今天 mysql查询上个月
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