PHP+JS三级菜单联动菜单实现方法
发布:smiling 来源: PHP粉丝网 添加日期:2021-07-11 13:08:50 浏览: 评论:0
这篇文章主要介绍了PHP+JS三级菜单联动菜单实现方法,涉及JavaScript动态控制页面样式及PHP数据库操作相关技巧,需要的朋友可以参考下,本文实例讲述了PHP+JS三级菜单联动菜单实现方法,分享给大家供大家参考,具体如下:
- <html>
- <head>
- <title>
- 智能递归菜单-读取数据库
- </title>
- <style>
- TD { FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; LINE-HEIGHT: 130%;
- letter-spacing:1px } A:link { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体";
- FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:visited
- { COLOR: #990000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:
- none; letter-spacing:1px } A:active { COLOR: #990000; FONT-FAMILY: "Verdana",
- "宋体"; FONT-SIZE: 12px; TEXT-DECORATION: none; letter-spacing:1px } A:hover
- { COLOR: #ff0000; FONT-FAMILY: "Verdana", "宋体"; FONT-SIZE: 12px; TEXT-DECORATION:
- underline; letter-spacing:1px } .Menu { COLOR:#000000; FONT-FAMILY: "Verdana",
- "宋体"; FONT-SIZE: 12px; CURSOR: hand }
- </style>
- <script language=javascript>
- function ShowMenu(MenuID) {
- if (MenuID.style.display == "none") {
- MenuID.style.display = "";
- } else {
- MenuID.style.display = "none";
- }
- }
- </script>
- </head>
- <body>
- <?php
- // $Id:$
- //基本变量设置
- $GLOBALS["ID"] = 1;
- //用来跟踪下拉菜单的ID号 $layer=1;
- //用来跟踪当前菜单的级数
- //连接数据库
- $Con=mysql_connect( "localhost", "root", "123456"); mysql_select_db(
- "menu");
- //提取一级菜单
- $sql="select * from menu where parent_id=0" ;
- $result=mysql_query($sql,$Con);
- //如果一级菜单存在则开始菜单的显示
- if(mysql_num_rows($result)>0) ShowTreeMenu($Con, $result, $layer, $ID);
- //=============================================
- //显示树型菜单函数 ShowTreeMenu($con,$result,$layer) //$con:数据库连接
- //$result:需要显示的菜单记录集
- //layer:需要显示的菜单的级数
- //=============================================
- function
- ShowTreeMenu($Con, $result, $layer) {
- //取得需要显示的菜单的项目数
- $numrows=mysql_num_rows($result);
- //开始显示菜单,每个子菜单都用一个表格来表示 echo "
- < tablecellpadding = '0'cellspacing = '0'border = '0' > "; for($rows=0;$rows
- <$numrows;$rows++) { //将当前菜单项目的内容导入数组 $menu=mysql_fetch_array($result);
- //提取菜单项目的子菜单记录集 $sql="select * frommenuwhereparent_id = $menu[id]" ; $result_sub=mysql_query($sql,$Con);
- echo " < tr > "; //如果该菜单项目有子菜单,则添加JavaScript onClick语句 if(mysql_num_rows($result_sub)>
- 0) { echo " < tdwidth = '20' > < imgsrc = 'tree_expand.gif'border = '0' > < / td > "; echo " < tdclass = 'Menu'onClick = 'javascript:ShowMenu(Menu".$GLOBALS["ID"].");' > "; } else { echo " < tdwidth = '20' > < imgsrc = 'tree_collapse.gif'border = '0' > < / td > "; echo " < tdclass = 'Menu' > "; } //如果该菜单项目没有子菜单,并指定了超级连接地址,则指定为超级连接, //否则只显示菜单名称 if($menu[url]!="")
- echo " < ahref = '$menu[url]' > $menu[name] < / a > "; else echo $menu[name]; echo " < / td > < / tr > "; //如果该菜单项目有子菜单,则显示子菜单 if(mysql_num_rows($result_sub)>0) { //指定该子菜单的ID和style,以便和onClick语句相对应
- echo " < trid = Menu".$GLOBALS["ID "]++ . " style='display:none'>";
- echo "<td width='20'></td>";
- echo "<td>";
- //将级数加1
- $layer++;
- //递归调用ShowTreeMenu()函数,生成子菜单
- ShowTreeMenu($Con,$result_sub,$layer);
- //子菜单处理完成,返回到递归的上一层,将级数减1
- $layer--;
- echo "< / td > < / tr > ";
- }
- //继续显示下一个菜单项目
- } echo " < / table > "; }
- ?>
- <?php
- $id=1 ;
- function test() {
- global $id; unset($id);
- }
- test();
- echo " < fontclass = menu > ".($id). " < / font > ";
- // 在 PHP 4 中这里会打印出 1
- ?>
- <?php
- $a=1 ;
- $b=2 ;
- function Sum() {
- global $a, $b; $b=$ a + $b;
- }
- Sum();
- echo " < fontclass = menu > ".$b. " < / font > ";
- ?>
- </body>
- </html>
Tags: PHP+JS三级菜单联动菜单
推荐文章
热门文章
最新评论文章
- 写给考虑创业的年轻程序员(10)
- PHP新手上路(一)(7)
- 惹恼程序员的十件事(5)
- PHP邮件发送例子,已测试成功(5)
- 致初学者:PHP比ASP优秀的七个理由(4)
- PHP会被淘汰吗?(4)
- PHP新手上路(四)(4)
- 如何去学习PHP?(2)
- 简单入门级php分页代码(2)
- php中邮箱email 电话等格式的验证(2)